In many ionic reactions not all the chemical species undergo a change. Those that do not change are called spectator ions. When chemists remove the spectator ions from a chemical reaction they produce what is termed a net ionic reaction. Net ionic equations indicate only the substance that undergo a change and are very important in our study of chemistry.
In order to write net ionic reactions we need to do the following steps:
Step #2 ; Writing the dissolving of ionic solids. (Arrhenius model )
- balance the equation for atoms.
- write out the dissolved chemical species as they exist in solution. Precipitates, liquids and gases are not written as ions. This is called a total ionic equation.
- remove common aqueous ions, ( ions that are in both the reactant and product) . The resulting equation is called the net ionic equation.
To write the dissolving of an ionic solid we:
Examples;
- place the formula for the ionic solid in the reactants.
- place the formulas for the ions that compose the solid in the products (taken from a table of ions)
- balance for the charge and atoms by changing the coefficients of the products.
1. Dissolving of Calcium Chloride
2. Dissolving of Barium Phosphate
Reactants ProductsWrite formulas of solid and ions CaCl2(s) __Ca 2+(aq) + __Cl-(aq)Balance for charge and atoms CaCl2(s) __Ca2+(aq) + 2 Cl -(aq)
Notice that in each case the numbers of atoms is balanced and so to is the charge in the products.
Reactant ProductFormulas Ba3(PO4)2(s) ___Ba 2+ (aq) + ___PO43- (aq)Balance Ba3(PO4)2(s) _3_Ba 2+ (aq) + _2_PO43- (aq)
The ratio of the ions to the solid always remains constant . If there were 2 CaCl2 (s) then we would have 2 Ca 2+ (aq) and 4 Cl - (aq) .
- There is + 2 , -2 for Calcium Chloride
- There is +6 and -6 for the Barium Phosphate.
How many Ba 2+ ions would be present if we had 3 Ba3(PO4)2 (s)? Answer 9.
Writing Net Ionic Equations (all three steps )A solution of Barium chloride combines with a solution of Sodium Carbonate to form a precipitate of Barium Carbonate and a solution of Sodium Chloride
1. Write the formula equations and balance
___BaCl2 (aq) + ___Na2CO3 (aq) ___BaCO3 (s) + _2__NaCl (aq)
2. Write the aqueous substances as separate ions. Leave solids, liquids and gases unchanged.
_Ba2+(aq) + 2Cl - (aq) + 2Na +(aq) + CO3 2-(aq) ___BaCO3 (s) + 2Na +(aq) + 2Cl- (aq)
3. Cancel common aqueous ions. (Net Ionic Equations )
Ba 2+ (aq) + CO32- (aq) BaCO3(s)
Assignment #3: Writing Net Ionic Equations
Balance the following reactions
Write the total and net ionic equations for the following using the procedure above.
- ___Zn (s) +___ HCl (aq) ----->___ ZnCl2 (aq) + ___H2 (g)
- ___FeCl3 (aq) +___ AgNO3 (aq) ------>___ AgCl (s) +___ Fe(NO3)3 (aq)
- ___KOH (aq) + ___H3PO4(aq) ------>___ K3PO4(aq) +___ H2O (l)
- ___HCl (aq) + ___ Na2CO3 (aq) -----> ___ H2O(l) + ___CO2(g) + ___NaCl (aq)
- ___Ba(OH)2 (aq) + ___Fe2(SO4)3 (aq) -----> ___ Fe(OH)3 (s) + ___ BaSO4 (aq)
- ___Mg (s) + ___AgNO3 (aq) -----> ___Ag (s) + ___ Mg(NO3)2 (aq)
- ___NaOH (aq) + ___CO2 (g) -----> ___Na2CO3 (aq) + ___H2O (l)
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